# CPC Section 422 Fixture Unit Calculations: Mastering Demand vs Supply Load
The ability to accurately calculate CPC Section 422 fixture unit calculations is fundamental to passing the California C-36 plumbing contractor exam. Yet many candidates struggle with the distinction between combination fixture unit demand versus supply load—a distinction that directly impacts pipe sizing, pressure requirements, and system design throughout the exam's Part 2 section on water supply and distribution systems.This comprehensive guide walks you through the theory, methodology, and practical application of fixture unit calculations so you can confidently tackle these problems on exam day.
Understanding CPC Section 422: Foundation Principles
What Are Fixture Units?
Fixture units represent a standardized measurement of water flow demand from plumbing fixtures. Rather than sizing every system based on actual gallons per minute (GPM), the California Plumbing Code (CPC) uses fixture units as a simplified calculation tool that accounts for fixture type, frequency of use, and duration of use.
CPC Section 422 establishes the methodology for determining water supply demand and defines both demand load and supply load fixture units. This section is your reference for:- Fixture unit assignments for various fixture types
- The distinction between demand and supply load calculations
- Combination fixture scenarios requiring simultaneous use considerations
- Special conditions and adjustments for specific applications
Demand Load vs Supply Load: The Critical Distinction
This is where most candidates stumble. These terms are not interchangeable: Demand Load Fixture Units represent the probability-adjusted load—acknowledging that not all fixtures operate simultaneously. This accounts for the statistical likelihood that some fixtures will be used concurrently while others remain idle. Demand load is used for sizing water supply pipes and determining required pressure. Supply Load Fixture Units represent the actual connected load—every fixture's full capacity added together, assuming simultaneous operation. Supply load is used for sizing main water supply lines and determining municipal connection requirements. The key principle: Supply load is always equal to or greater than demand load because demand load applies a simultaneous use probability factor.CPC Section 422 Table Methodology
Reading the Fixture Unit Tables
CPC Section 422 provides Table 422.1, which lists fixture types with their corresponding fixture unit values. Understanding how to read this table is essential:
Common Fixture Unit Values (Supply Load):- Toilet (flushometer valve): 6 units
- Toilet (tank): 3 units
- Lavatory: 1 unit
- Bathtub: 2 units
- Shower: 2 units
- Sink (kitchen): 2 units
- Dishwasher: 1.4 units
- Washing machine: 2 units
- Water closet (urinal): 4 units (flushometer) / 2 units (tank)
Applying Demand Factors
The critical step many candidates miss: once you calculate total supply load, you must apply a demand factor to determine demand load. CPC Section 422 provides demand factor tables based on:- Total number of fixtures
- Building occupancy type (residential, commercial, etc.)
- Fixture combinations
- 1-2 fixtures: 100% (1.0)
- 3-5 fixtures: 68% (0.68)
- 6-8 fixtures: 47% (0.47)
- 9-10 fixtures: 39% (0.39)
- 20+ fixtures: 27% (0.27)
Combination Fixture Unit Demand vs Supply Load Scenarios
Single-Use Vs Combination Fixtures
Many exam questions involve combination fixtures—fixtures that serve multiple purposes. Common examples include:
- Bathroom groups (toilet + lavatory + bathtub/shower)
- Kitchen combinations (sink + dishwasher)
- Laundry combinations (washer + utility sink)
- Supply Load: 3 + 1 + 2 = 6 units
- Demand Load: 3.6 units (60% demand factor for bathroom groups)
Step-by-Step Calculation Process
Let's work through a complete example to illustrate the methodology:
Problem: Calculate both supply and demand load for a small office building with:- 3 toilets (tank type)
- 3 lavatories
- 2 emergency eyewash stations (1 unit each)
- 1 water cooler (0.25 units)
- Toilets: 3 × 3 = 9 units
- Lavatories: 3 × 1 = 3 units
- Eyewash stations: 2 × 1 = 2 units
- Water cooler: 0.25 units
- Total Supply Load = 14.25 units
- Commercial office building
- 9 total fixtures
- Non-residential classification
- Demand Load = 14.25 × 0.40 = 5.7 units
Pressure-Related Fixture Unit Calculations
Low-Pressure vs Standard Pressure Fixtures
Some fixtures operate at reduced pressure (below 20 PSI). CPC Section 422 recognizes this with adjusted fixture unit values for:
- Low-pressure toilet tanks (reduced fixture units)
- Pressure-reducing valve applications
- Building pressure systems
Common Calculation Errors to Avoid
Error 1: Confusing Demand and Supply Load
Mistake: Students add all fixture units and assume this equals demand load. Correction: Supply load = sum of all fixtures. Demand load = supply load × demand factor.Error 2: Forgetting Bathroom Group Adjustments
Mistake: Calculating bathroom components separately rather than applying the combination fixture rule. Correction: When toilet + lavatory + tub/shower appear together, apply the bathroom group factor (approximately 60% demand).Error 3: Misapplying Commercial vs Residential Factors
Mistake: Using residential demand factors for commercial buildings or vice versa. Correction: Always identify building type first. Commercial buildings (offices, retail) have different factors than residential (apartments, homes).Error 4: Ignoring Special Fixture Classifications
Mistake: Treating all fixtures identically when CPC Section 422 provides special rules for appliances and special-use fixtures. Correction: Cross-reference less common fixtures (lab equipment, medical fixtures, commercial washing machines) in CPC Table 422.1.Real-World Application: Sizing Water Supply Piping
Understanding fixture unit demand vs supply load directly impacts how you size distribution piping—a frequent exam topic.
Determining Pipe Diameter
The demand load determines the flow rate, which determines required pipe diameter:
Example: A residential system with 12 fixtures calculates as:- Supply Load: 24 units
- Demand Factor (residential, 12 fixtures): 0.33
- Demand Load: 24 × 0.33 = 7.92 units
CPC Section 422 Table References for the C-36 Exam
Memorize these key table sections:
- Table 422.1: Fixture unit assignments (supply load)
- Table 422.2: Demand factors (residential and commercial)
- Table 422.3: Combination fixture demand loads
- Table 422.4: Pressure requirements and adjustments
Practice Problem Set
Problem 1: Residential Apartment
An apartment has:- 1 toilet (tank)
- 1 lavatory
- 1 shower
- 1 kitchen sink
- 1 dishwasher
- Supply: 3 + 1 + 2 + 2 + 1.4 = 9.4 units
- Demand factor (5 fixtures, residential) = 0.68
- Demand: 9.4 × 0.68 = 6.39 units
Problem 2: Small Office
An office has:- 2 toilets (flushometer)
- 2 lavatories
- 1 water cooler
- 1 utility sink
- Supply: (2 × 6) + (2 × 1) + 0.25 + 2 = 16.25 units
- Demand factor (6 fixtures, commercial) ≈ 0.40
- Demand: 16.25 × 0.40 = 6.5 units
Key Takeaways for Exam Success
- Always distinguish between supply load (sum of all fixtures) and demand load (supply × demand factor)
- Memorize common fixture units: toilet (3-6), lavatory (1), shower/tub (2), sink (2)
- Apply combination fixture rules when bathroom groups appear together
- Reference correct demand factors based on building type and fixture count
- Remember: Supply load is always greater than or equal to demand load
- Practice calculations under timed conditions to build speed and accuracy
Exam Strategy Tips
- Read questions carefully to identify whether they ask for supply or demand load—the answer changes dramatically
- Show your work on calculations to catch errors and receive partial credit
- Use margin notes to organize your calculation steps
- Double-check demand factors against the correct table for building type
- Verify units (are you calculating for 3 fixtures or 30?)
Begin practicing today with the problems provided in this guide, and your Part 2 water supply and distribution systems performance will improve significantly.





